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Bacsinszky beats Wickmayer to reach L'bourg final

October 24, 2009 - 12:05pm
Belgium's Yanina Wickmayer reacts during the semi final of the Luxembourg Open WTA tennis tournament against Switzerland's Timea Bacsinszky in Luxembourg, Saturday Oct. 24, 2009. (AP Photo/Yves Logghe)

LUXEMBOURG (AP) - Switzerland's Timea Bacsinszky defeated fifth-seeded Belgian Yanina Wickmayer, 3-6, 6-2, 7-5 on Saturday to make the finals of the Luxembourg Open.

Bacsinszky struggled in the third set to keep her lead, as Wickmayer fought back to tie the set 5-5 before the Swiss player won the match after the Belgian hit the ball into the net.

Bacsinszky will play for her first WTA Tour single's title on Sunday against either Shahar Peer from Israel or sixth-seeded Sabine Lisicki of Germany.


(Copyright 2009 The Associated Press. All rights reserved. This material may not be published, broadcast, rewritten or redistributed.)


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AP material Copyright 2009 Associated Press. All rights reserved. This material may not be published, broadcast, rewritten, or redistributed.